(n^2-n-29)/(n-6)

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Solution for (n^2-n-29)/(n-6) equation: 


D( n )

n-6 = 0

n-6 = 0

n-6 = 0

n-6 = 0 // + 6

n = 6

n in (-oo:6) U (6:+oo)

(n^2-n-29)/(n-6) = 0

n^2-n-29 = 0

n^2-n-29 = 0

DELTA = (-1)^2-(-29*1*4)

DELTA = 117

DELTA > 0

n = (117^(1/2)+1)/(1*2) or n = (1-117^(1/2))/(1*2)

n = (3*13^(1/2)+1)/2 or n = (1-3*13^(1/2))/2

(n-((1-3*13^(1/2))/2))*(n-((3*13^(1/2)+1)/2)) = 0

((n-((1-3*13^(1/2))/2))*(n-((3*13^(1/2)+1)/2)))/(n-6) = 0

( n-((1-3*13^(1/2))/2) )

n-((1-3*13^(1/2))/2) = 0 // + (1-3*13^(1/2))/2

n = (1-3*13^(1/2))/2

( n-((3*13^(1/2)+1)/2) )

n-((3*13^(1/2)+1)/2) = 0 // + (3*13^(1/2)+1)/2

n = (3*13^(1/2)+1)/2

n in { (1-3*13^(1/2))/2, (3*13^(1/2)+1)/2 }

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